Purpose: To find the individuality of an unknown metal
Hypothesis: The unknown metal is Copper
* Safety spectacless
* Styrofoam cup
* Thread or twine
* Glass rod
* Thermometer
* 100mL graduated cylinder
* Hot home base
* Balance
* Unknown metal
* 300mL beaker

I. Mass of metal was recorded
two. Water was heated on a hot home base in beaker
three. Temperature was recorded when H2O reached a furuncle
four. Cold H2O was put into graduated cylinder
v. Mass of H2O was recorded
six. Cold H2O was poured into Styrofoam cup
seven. Temperature of cold H2O was recorded
eight. Metal was removed from hot H2O and was placed into cold H2O nine. Temperature alteration in cold H2O was recorded

| Cold Water| Metal|
M ( kilogram ) | 0. 117 kg| 0. 07062 kilogram |
T1 ( C ) | 98C| 81C|
T2 ( C ) | 20C| 20C|
T ( C ) | 2 C| -61C|
C ( J/kgC ) | 4. 2 ten 103 |

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mwcwTw= -mmcmTm
centimeter = mwcwTw /-mmTm

= ( 0. 117 ) ( 4. 2?103 ) ( 2 ) / ( -0. 07062 ) ( -61 )
centimeter = 228. 14
~ 2. 3?102 ( Silver )
The unknown metal was Ag

1. I found the specific heat capacity of my unknown metal in my text edition on page 260 because no metals in the chart matched the computation I got. 2. Two beginnings of mistake for this experiment would be that we can non find the existent temperature of the interior of the metal so we merely have to presume it is even through. and that our H2O temperatures changed after we recorded them and before we took the metal out. altering the temperature of the metal so our computations were non exact. 3. A ) Water has a higher specific heat capacity

B ) Rock would heat up faster ( given the same sum of energy ) because it takes more heat energy to alter Waterss temperature by one grade Celsius C ) Rock would lose heat faster because it gained heat faster 4. At a beach in July. a stone on the shore would experience warm while the H2O would still experience cold because the stone which has been in the Sun all twenty-four hours heats up faster than the H2O due to its lower specific heat capacity. Besides the H2O has a greater surface country than the stone so it would take longer to heat up. 5. They are located further from the big organic structures of H2O 6. They are located right by the big organic structures of H2O

7. That big organic structures of H2O moderate temperatures. non giving them really high temperatures or really cold temperatures 8. In the center of the state ( like Toronto ) for illustration. because it isn’t near a big organic structure of H2O. which would assist maintain the temperature at a moderate grade. 9. Lakes and oceans moderate the clime because the specific heat capacity of H2O is high. intending it takes a batch of energy to alter the temperature of H2O. So. during the summer. land countries near a big organic structure of H2O may non heat up every bit much as countries that are non near to H2O. because the H2O itself is adsorbing much of the heat energy. This will do the clime to be more moderate in summer near the seashore. for illustration. Likewise in winter. the H2O near the seashore will slowly release this energy. doing countries near big organic structures of H2O to be less cold. in general. than land countries that are non.

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